X^2+18x=35

Solution for X^2+18x=35 equation:

X^2+18X=35

We move all terms to the left:

X^2+18X-(35)=0

a = 1; b = 18; c = -35;
Δ = b2-4ac
Δ = 182-4·1·(-35)
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-4\sqrt{29}}{2*1}=\frac{-18-4\sqrt{29}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+4\sqrt{29}}{2*1}=\frac{-18+4\sqrt{29}}{2}
$